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Anisotropies

There is no reason to expect that the mineralization will exhibit the same behavior in every direction, i.e., that the mineralization will be isotropic. In the three-dimensional space, x represents the coordinates $(x_u, x_v, x_w)$ and ${/boma h}$ represents a vector of modulus $/vert{/boma h}/vert$ and direction ${/boma /alpha}$. Thus, in condensed form, $/gamma({/boma h})$ represents the set of semi-variograms $/gamma(/vert{/boma h}/vert, {/boma /alpha})$ for each direction ${/boma /alpha}$. By studying $/gamma({/boma h})$ in various directions ${/boma /alpha}$, it would be possible to determine any possible anisotropies, such as the variability of the range $a({/boma /alpha})$ with the direction ${/boma /alpha}$. In the example of Figure 1.3, the semi-variogram for the vertical direction reveals a short range $a_1$ corresponding to the mean vertical width of the mineralized lenses, while the semi-variogram for the horizontal direction has a larger range $a_2$ corresponding to the mean horizontal dimensions of the same lenses. The directional graph of ranges $a({/boma /alpha})$ thus represents the average morphology of the mineralized lenses.



Rudolf Dutter 2003-03-13